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来源:未知 时间:2015-07-27 13:34 作者:xxadmin 阅读:次
[导读] 这篇文章主要介绍了JavaScript数据库TaffyDB用法,实例分析了TaffyDB数据库的定义、查询、更新、删除等操作的相关使用技巧,具有一定参考借鉴价值,需要的朋友可以参考下 TaffyDB 是一个免费...
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这篇文章主要介绍了JavaScript数据库TaffyDB用法,实例分析了TaffyDB数据库的定义、查询、更新、删除等操作的相关使用技巧,具有一定参考借鉴价值,需要的朋友可以参考下 TaffyDB 是一个免费开源的 JavaScript 库,用于在 Web 上实现一个轻量级的数据访问层,也就是一个简单的数据库。 数据定义: var friends = new TAFFY(
[
{name:"Bob",
gender:"M",
married:"No",
age:25,
state:"NY",
favorite_foods:["pizza","tacos"]},
{name:"Joyce",
gender:"F",
married:"No",
age:29,
state:"WA",
favorite_foods:["salad","cheese sticks"]},
{name:"Dan",
gender:"M",
married:"No",
age:29,
state:"MT",
favorite_foods:["pizza","hamburgers","BLTs"]},
{name:"Sarah",
gender:"F",
married:"No",
age:21,
state:"ID",
favorite_foods:["pizza","sushi"]}
]
)查询: friends.find({age:{greaterthan:22}});
friends.find({state:["WA","MT","ID"]});
friends.find({state:["WA","MT","ID"],
age:{greaterthan:22}});更新操作: friends.update(
{
state:"CA",
married:"Yes"
},
{
name:"Joyce"
}
);
friends.update({state:"CA",married:"Yes"},1);
friends.update(
{
state:"CA",
married:"Yes"
},
friends.find(
{name:"Joyce"}
)
);插入数据: //Inserting is simple and works as you would expect:
friends.insert(
{name:"Brian",
gender:"M",
married:"No",
age:52,
state:"FL",
favorite_foods:["fruit","steak"]
});删除: friends.remove({name:"Brian"});排序: friends.orderBy(["age",{"name":"desc"}]);
var keys = new TAFFY([
{name:"12abc"},
{name:"abc343"},
{name:"1abc"},
{name:"23abc"}
]);
keys.orderBy({name:"logical"});forEach用法: friends.forEach(function (f,n) {alert(f.name)});
friends.forEach(
function (f,n) {alert(f.name);},
{favorite_foods:{has:"pizza"}}
); |
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